How much heat is produced by the combustion of 131 g of propane (C3H8)? C3H8(g) + 5O2(g) ⟶ 3CO2(g) + 4H2O(l) ΔH° = -2220 kJ/mol Select the correct answer below: A) 1.32 × 10^4 kJ B) 6.60 × 10^3 kJ C) 747 kJ D) 2.91 × 10^5 kJ
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Step 1
Given: Mass of propane (C3H8) = 131 g Molar mass of propane (C3H8) = 44 g/mol Number of moles = Mass / Molar mass Number of moles = 131 g / 44 g/mol Number of moles = 2.98 mol Show more…
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