Given that the radius of the event horizon is 3.35 cm (3.35 x 10^-2 m), we can plug in the values:
\(3.35 \times 10^{-2} = \frac{2 \times 6.67 \times 10^{-11} \times M}{(3 \times 10^8)^2}\)
Solving for \(M\), we get:
\(M = \frac{3.35 \times 10^{-2} \times (3
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