How much work is done to move an electron with a charge of –1.6  10–19 C from the positive terminal of a 1.5-V battery to the negative terminal?
Added by Evans K.
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We know the charge of the electron (q) is -1.6 x 10^-19 C. Show more…
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How much work is required to carry an electron from the positive terminal of a 12-V battery to the negative terminal? Going from the positive to the negative terminal, one passes through a potential drop. In this case it is $V=-12 \mathrm{~V}$. Then $$ W=q V=\left(-1.6 \times 10^{-19} \mathrm{C}\right)(-12 \mathrm{~V})=1.9 \times 10^{-18} \mathrm{~J} $$ As a check, notice that an electron, if left to itself, will move from negative to positive because it is a negative charge. Hence, positive work must be done to carry it in the reverse direction as required here.
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