How to solve:which element is in excess when 3.00 grams of Mg is ignited with 2.20 grams of pure oxygen?
Added by Whitney C.
Step 1
The molar mass of Mg is 24.31 g/mol and the molar mass of O2 is 32.00 g/mol. Moles of Mg = (3.00 g) / (24.31 g/mol) = 0.123 mol Moles of O2 = (2.20 g) / (32.00 g/mol) = 0.0688 mol Now, we need to find the mole ratio of Mg to O2 in the balanced chemical equation Show more…
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