Given:
Length of pendulum, L = 1m
Acceleration due to gravity, g = 9.81 m/s^2
The time period of oscillation of a simple pendulum is given by:
\[ T = 2\pi \sqrt{\frac{L}{g}} \]
Substitute the values:
\[ T = 2\pi \sqrt{\frac{1}{9.81}} \]
\[ T = 2\pi \sqrt{0.102}
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