00:01
In this problem, we're given some different alcohols and we're asked how we would prepare them using greenered reagents.
00:08
So remember that a greenered reagent is going to be magnesium and halogen, and it's going to be attached to some carbon.
00:22
And magnesium will have a partial positive, giving carbon a partial negative charge.
00:28
So we'll attack at the carbonyl.
00:31
And this adds carbons but also when you protonate it we get an alcohol so with that in mind if we look here in our first structure if we had an aldehyde like this then we would add these carbons to it so we'd have our magnesium bromide and then we'd have ch2 ch2 ch3 all right so then if we look at our next structure, we have our oh on the end.
01:19
So that tells us we have one carbon here that had our oh.
01:28
So if we start with formaldehyde, so only one carbon, then we add our other three carbons here.
01:49
Now our next one, we have our alcohol coming off our ring...