Question

HTET-PGT-PHY... [D] 118. Steam at 100°C is passed into 20 gm of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be: take specific heat of water = 1 cal g?¹ °C?¹ and latent heat of steam = 540 cal g?¹ [1] 22.5 gm [2] 23.5 gm [3] 24.5 gm [4] 21.5 gm

          HTET-PGT-PHY...
[D]
118. Steam at 100°C is passed into 20 gm
of water at 10°C. When water
acquires a temperature of 80°C, the
mass of water present will be:
take specific heat of water = 1 cal
g?¹ °C?¹ and latent heat of steam
= 540 cal g?¹
[1] 22.5 gm
[2] 23.5 gm
[3] 24.5 gm
[4] 21.5 gm

HTET-PGT-PHY...
[D]
118. Steam at 100°C is passed into 20 gm
of water at 10°C. When water
acquires a temperature of 80°C, the
mass of water present will be:
take specific heat of water = 1 cal
g?¹ °C?¹ and latent heat of steam
= 540 cal g?¹
[1] 22.5 gm
[2] 23.5 gm
[3] 24.5 gm
[4] 21.5 gm

Added by Robert B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Yatu Khandelwal

03/01/2022

Step 1

Step 1: Let the mass of steam condensed be m gm. Show more…

Show all steps

Thanks for your feedback!

<HTET-PGT-PHY... : [D] 118. Steam at 100°C is passed into 20 gm of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be: take specific heat of water = 1 cal g⁻¹ °C⁻¹ and latent heat of steam = 540 cal g⁻¹ [1] 22.5 gm [2] 23.5 gm [3] 24.5 gm [4] 21.5 gm - ne/natprime