Consider the circuit shown below where the battery has an emf of ? = 18.1 V, the resistors have the resistances of R?=1.1 ?, R? = R? = 4.7 ?, and the capacitance of the capacitor is C=2.6 F. The switch S is closed at t=0. The capacitor is initially uncharged. If you wait long enough after the switch is closed, at t=?, what is the current running through R?? Please express your answer using two decimal places in units of Ampere (A).
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When the switch is closed, the circuit forms a loop with the battery and the resistors R1, R2, and R3. The capacitor will start charging. Show more…
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Consider the circuit shown below where the battery has an emf of ε = 8.2 V, the resistors have the resistances of R1=2.3 Ω, R2 = R3 = 6.6 Ω, and the capacitance of the capacitor is C=1.4 µF. The switch S is closed at t=0. The capacitor is initially uncharged. If you wait long enough after the switch is closed, at t=∞, what is the current running through R3? Please express your answer using one decimal place in units of Ampere (A).
Prabhu R.
please answer my questions thank
please answer my questions thanks
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