'HW. An abc-phase-sequence three-phase voltage source connected in a balanced wye has line voltage of Vab 208/ Vrms_ Determine the phase voltages of the source.'
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Step 1: Determine the line voltage VAB VAB = 208 Vrms Show more…
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In a balanced three-phase wye-wye system, the source is an $a b c$ -sequence set of voltages and $\mathbf{V}_{a n}=120 / 50^{\circ} \mathrm{V} \mathrm{rms}$ The load voltage on the $a$ phase is $110 / 50^{\circ} \mathrm{V} \mathrm{rms}$, and the load impedance is $16+j 20 \Omega$. Find the line impedance.
A three-phase source delivers 4800 VA to a wye-connected load with a phase voltage of $208 \mathrm{V}$ and a power factor of 0.9 lagging. Calculate the source line current and the source line voltage.
A balanced positive-sequence wye-connec. ted $60-\mathrm{Hz}$ three -phase source has linc-to-linc voltages of $V_{L}=208 \mathrm{V} \mathrm{rms}$. This source is connected to a balanced wye-connected load. Each phase of the load consists of an impedance of $30+j 40 \Omega$. Find the line to-neutral voltage phasors, the line-to-line voltage phasors, the line-current phasors, the power, and the reactive power delivered to zero.
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