Question

1 1+2 N F F XB network 1-3 N 3 N R R? R 3+2 N R2 OH HO OHN R4 R3 HO R3 HB network R4 2a R1,R2,R3,R = H 2b R1,R2,R3H R?=F 2c R1,R2,R3.R4 = F 2a-3 R1,R2,R3,R = H 2b-3 R1,R2,R3 = H R?=F 2c-3 R1,R2,R3,R = F Scheme 1 Synthesis of hydrogen-bonded (HB) and halogen-bonded (XB) co-crystals. Co-crystallization of XB donor 1 or HB donor 2 with 1,2-bis(4-pyridyl)ethane 3 to form the XB network 1-3 or HB network as 2-3, respectively.

          1
1+2
N
F
F
XB network 1-3
N
3 N
R R?
R
3+2
N
R2
OH
HO
OHN
R4 R3
HO
R3
HB network
R4
2a R1,R2,R3,R = H
2b R1,R2,R3H R?=F
2c R1,R2,R3.R4 = F
2a-3 R1,R2,R3,R = H
2b-3 R1,R2,R3 = H R?=F
2c-3 R1,R2,R3,R = F
Scheme 1 Synthesis of hydrogen-bonded (HB) and halogen-bonded
(XB) co-crystals. Co-crystallization of XB donor 1 or HB donor 2 with
1,2-bis(4-pyridyl)ethane 3 to form the XB network 1-3 or HB network
as 2-3, respectively.

1
1+2
N
F
F
XB network 1-3
N
3 N
R R?
R
3+2
N
R2
OH
HO
OHN
R4 R3
HO
R3
HB network
R4
2a R1,R2,R3,R = H
2b R1,R2,R3H R?=F
2c R1,R2,R3.R4 = F
2a-3 R1,R2,R3,R = H
2b-3 R1,R2,R3 = H R?=F
2c-3 R1,R2,R3,R = F
Scheme 1 Synthesis of hydrogen-bonded (HB) and halogen-bonded
(XB) co-crystals. Co-crystallization of XB donor 1 or HB donor 2 with
1,2-bis(4-pyridyl)ethane 3 to form the XB network 1-3 or HB network
as 2-3, respectively.

Added by Gregory G.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

03/07/2023

Step 1

In less polar solvents, the hydrogen bonding interactions are favored due to the ability of the solvent molecules to interact with the hydrogen bond donors and acceptors. Show more…

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Hydrogen-bonded co-crystals form in the least polar solvents and halogen-bonded co-crystals in the more polar solvents. Explain this in terms of solvent effect. as 2.3. respectively 2cR.R.Rg.R=F 2bR.R,R=HR=F 2aR.RR.R=H R HO OH T 3+2 1.2-bis4-pyridyllethane 3 to form the XB network 1.3 or HB.network XB) co-crystals. Co-crystallization of XB donor 1 or HB donor 2 with Scheme 1 Synthesis of hydrogen-bonded (HB) and halogen-bonded HO- 2 OH-N 2c3 R.R.Rg.R4=F 2b-3R.RR=HR=F 2a-3 R.R.R.R=H HB network XB network 1-3