Hydrogen gas, H2, reacts with nitrogen gas, N2, to form ammonia gas, NH3, according to the equation 3H2(g) + N2(g) → 2NH3(g). How many moles of NH3 can be produced from 18.0 mol H2 and excess N2? Express the answer numerically in grams.
Added by Ralph C.
Step 1
0 mol of H2. Given: 18.0 mol H2 Using the balanced equation: 3H2(g) + N2(g) → 2NH3(g) For every 3 moles of H2, 2 moles of NH3 are produced. Therefore, 18.0 mol H2 * (2 mol NH3 / 3 mol H2) = 12.0 mol NH3 produced Show more…
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