00:01
Hi, in the question it is given that, given that capacity of battery is equal to 1 5 that is 15 kilowatt.
00:20
So in watt it will be 15 multiplied by 1000 which is equal to 15000 watt.
00:31
So we have to find range when battery is new.
00:34
So we have, so when battery is new, effective capacity that can be used will be equal to 85 upon 100 multiplied by 15000.
00:48
So 20 will get cancelled by 20 and we will have 12750 watt.
00:56
Let us take this as equation 1.
00:58
Given that energy consumed per kilometer is equal to 80 watt.
01:05
So range will be equal to effective capacity of battery upon energy consumed per kilometer.
01:12
So this will be equal to 12750 upon 80.
01:19
So this will give 159 .375 kilometer.
01:26
So range when battery is new will be equal to 159 .375 kilometer.
01:51
Now at the end of life, effective capacity that can be used will be equal to 70 upon 100 multiplied by 15000.
02:22
So 20 will get cancelled by 2 and we will have 10500 watt.
02:31
Let us take this as equation 2.
02:34
Now it is, now it is given that energy consumed by kilometer is equal to 80 watt.
02:42
So we will have range is equal to effective capacity of battery upon energy consumed per kilometer.
02:47
So this will be equal to 10500 upon 80.
02:52
So this will give 131 .25 kilometer.
02:58
So therefore we can say, so range when battery at the end of life will be equal to 131 .25.
03:04
Now in the second part, we will find range only and it is given that power consumed by auxiliary power supply will be equal to 500 watt...