00:01
All right, so let's say we have a vector a that has the form i -hat plus j -hat, and we want to know what is the magnitude of a.
00:08
So this is going to be the square root of the i -hat coefficient, which is one squared, plus the j -hat coefficient, which is also one squared.
00:18
And so this is just the square root of two.
00:20
So it's about 1 .41.
00:22
And then the direction is going to be the inverse tangent of the y component, which is one over the x component, which is also one.
00:30
And so this is a 45 degree angle.
00:33
And let's say we have another vector b, which is i -hat minus j -hat.
00:37
Now, this is going to have the same magnitude as the previous one.
00:41
It's a square root of two.
00:43
But the direction now is going to be different...