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Hello everyone.
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So in this problem density of gas is 1 .43 gram per liter at a temperature of 23 degrees celsius and a pressure of 0 .789 atm.
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So calculate the molar mass of the gas.
00:11
So we are given density of gas that is equal to 1 .43 gram per liter temperature 23 degrees celsius we can convert into kelvin by adding 273 which we get temperature in terms of kelvin to 96 kelvin.
00:22
So density value is given temperature is 296 kelvin pressure that is 0 .789 atm that is also given.
00:30
Molar mass of the gas that we have to find out.
00:32
So we can apply the concept of ideal gas equation to find the molar mass of the gas.
00:38
According to idle gas equation, we have pv is equal to nrt where p is the pressure, v is the volume, n is number of mall of gas, r is gas constant and t is the temperature.
00:47
A number of mall of gas can be written as mass divided by molar mass.
00:50
So this capital m represent molar mass of the gas and this small m represent mass of the gas.
00:58
So i can write pv is equal to mass upon molar mass into r t so rearrange this equation p into m that is equal to mass upon volume into r t so this term basically mass upon volume that is known as density because density is simply mass upon volume right so this is the formula of density.
01:17
So i can write p m is equal to d rt where d is the density of the gas...