00:01
Hello students, to find an orthogonal matrix p and a diagonal matrix d such that d equal to p transpose ap, we need to perform a diagonalization of the given matrix i .e.
00:13
A equal to minus 19, 4, minus 8, 4, minus 25, minus 4, minus 8, minus 4, minus 19.
00:26
First we find the eigenvalues of a by determining the characteristic equation that we can find by determinant a minus lambda i equal to 0.
00:40
So, where lambda is an eigenvalue and i is the identity matrix.
00:56
So, a minus lambda i equal to minus 19 minus lambda, 4 minus 18, 4, minus 25, minus lambda, minus 4, minus 8, minus 4, minus 19, minus lambda.
01:13
Expanding the determinant, we have minus 19 minus lambda into minus 25 minus lambda, minus 19 minus lambda, minus minus 4, minus 4, minus 4 into 4 into 19 minus lambda, minus 19 minus lambda, minus minus 8 into minus 4, minus 8 into 4 into minus 4, minus minus 8 into minus 25 minus lambda equal to 0.
02:04
Simplifying and solving the equation, we will find lambda 1 equal to minus 40, lambda 2 equal to minus 20 and lambda 3 equal to minus 3.
02:15
Now, next we find the corresponding eigenvector of each eigenvalue.
02:20
So, for lambda equal to minus 40, substituting lambda 1 equal to minus 40 and solving the system of equation, we find x1 equal to 1, minus 1, minus 1.
02:44
For lambda 2 equal to minus 20, we have x2 equal to minus 2, 1, 0 and for lambda 3 equal to minus 3, x3 equal to 1, 0, minus 2...