Question

ASSESSMENT PROBLEM Objective 5—Be able to analyze circuits with ideal transformers 9.15 The source voltage in the phasor domain circuit in the accompanying figure is $25\angle 0^\circ$ kV. Find the amplitude and phase angle of $V_2$ and $I_2$. Answer: $V_2 = 1868.15 \angle 142.39^\circ$ V; $I_2 = 125 \angle 216.87^\circ$ A. NOTE: Also try Chapter Problem 9.82.

          ASSESSMENT PROBLEM
Objective 5—Be able to analyze circuits with ideal transformers
9.15 The source voltage in the phasor domain circuit
in the accompanying figure is $25\angle 0^\circ$ kV. Find
the amplitude and phase angle of $V_2$ and $I_2$.
Answer: $V_2 = 1868.15 \angle 142.39^\circ$ V;
$I_2 = 125 \angle 216.87^\circ$ A.
NOTE: Also try Chapter Problem 9.82.

ASSESSMENT PROBLEM
Objective 5—Be able to analyze circuits with ideal transformers
9.15 The source voltage in the phasor domain circuit
in the accompanying figure is 25∠ 0^∘ kV. Find
the amplitude and phase angle of V2 and I2.
Answer: V2 = 1868.15 ∠ 142.39^∘ V;
I2 = 125 ∠ 216.87^∘ A.
NOTE: Also try Chapter Problem 9.82.

Added by Justin H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Surendra Kumar

Step 1

The given source voltage is 25/0 kV. To convert it to polar form, we need to find the amplitude and phase angle. The amplitude (V) can be found using the formula: V = √(Real^2 + Imaginary^2) In this case, the real part is 25 and the imaginary part is 0. Show more…

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I keep getting the wrong answer for I2 no matter what :/ Please do neat handwriting so I can follow along. Thanks! ASSESSMENT PROBLEM Objective 5 - Be able to analyze circuits with ideal transformers 9.15 The source voltage in the phasor domain circuit in the accompanying figure is 25/0 kV. Find the amplitude and phase angle of V and I. 1.5 k j6 k W 1 40 j14.4 Answer: V = 1868.15/142.39 V; I2 = 125/216.87 A. NOTE: Also try Chapter Problem 9.82