MGT 2040 Homework: Section 9.1 Homework 9.1.10-T A sample...

MGT 2040 Homework: Section 9.1 Homework 9.1.10-T A sample taken from a population yields a sample mean of 60.4. Calculate the p-value for parts a through d below. a. HA : ? > 60, n = 16, ? = 0.8 b. HA : ? ? 45, n = 41, s = 33.089 c. HA : ? ? 45, n = 41, ? = 33.089 d. HA : ? < 69; data: 60.2, 59.6, 57.2, 57.8, 67.2 a. Calculate the p-value for HA : ? > 60, n = 16, ? = 0.8. The p-value for this test is (Round to three decimal places as needed.)

Transcript

00:01 Hi, i'm david and i'm here to have your answer your question.

00:04 In the question here we are going to discuss about the hyperstesting.

00:08 Here we have the four questions, apcd, and for each of them we need to compute the p value for each.

00:16 For the a, we're given the alternative hypothesis, mean equal to mean greater than the 60, and n equal to the 16, sigma equal to the 6, sigma equal to the zabon 8 so the first thing you find will be the test statistics z because we have the sigma is known equal to the x bar minus the mean of a sigma divided by square of n then we have the x bar here it will equal to here we are not given the oh so we have the sum of mean all of them we have the same symbol mean x bar equal to the 60 .4 so if we turn the 60 one form we minus the 60 divided by 0 .8 of square in the 16 then we get 0 1 4 divided by 018 times 4 equal to the 2 and then we have the b value equal to the probability the z whether than the volume of the 2 now i can compute this one using the normal distribution here i will have the normal distribution and with the value of the 2 we get equal to the japan 0 -2 -275 and that's going to be the answer for the first part a we need to write to the 3 decimal classes equal to the 0 0 2 3.

02:07 Now for the question p we are given the arch a it will equal mean here we will not equal to the 45 and the n equal to the 41 and the 6 and the s now here equal to the 33 .089 and then we have to find the test statistics now that will be the t because we are given the s.

02:33 So again the same formula x by minus mean over s divided by square the end then we have the 60 .4 minus the mean will be the 45 divided by the 33 .080.

02:46 Over square root of the 41 and then we get equal to 45 divided 33 .089 times square root of the 41 equal to the 2 .98.

03:01 Then the p value here because there will be the two tails test we have to turn the two times the probability of the t with the n minus 1 degree that would be the 40 greater than the test statistics.

03:17 And to find this value, i will use the distribution with the 40 degree freedom and greater than the 2 .98...

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