00:01
For this question, we'll carry out calculations for each of the two trials.
00:06
First, we need to calculate the temperature difference.
00:09
That's just going to be the final temperature minus the initial temperature.
00:13
For the first trial, 30 minus 22 is 8.
00:17
For the second trial, 30 .9 minus 22 is 8 .9.
00:22
Then the total mass, assuming that the density of the solution is one gram per milliliter, which they suggest, we get a total of 200 milliliters upon mixing.
00:33
So, i'm sorry, we get 50 milliliters plus 50 milliliters.
00:42
So that gives us 100 milliliters, or 100 grams.
00:47
So these are 100, not 200.
00:53
Oops.
00:57
And then for q, that's going to be the specific heat of water multiplied by the mass of the solution, which again is 100 grams, multiplied by the change in temperature, which for this first trial was 8 degrees celsius.
01:20
Then we convert the joules to kilojoules by dividing by a thousand, and that gives us 6, actually 3 .35 kilojoules.
01:44
And then for the next one, we end up getting, i need to change that 200 to 100, we get 3 .723 kilojoules...