Question

The average price for a movie ticket in a certain country in 2018 was $9.74. A random sample of 34 movie ticket prices in a major city in that country had a sample mean of $13.15 with a standard deviation of $3.09. a. Do we have evidence that the price of a movie ticket in that city is different from the national average? Use a significance level of 0.05. b. Construct a 95% confidence interval for the price of a movie ticket in that city. How does your confidence interval support your conclusion in part (a)? a. Determine the null and alternative hypotheses. Choose the correct answer below. ? ?. $H_0: \mu \neq \$9.74$ $H_a: \mu = \$9.74$ ? D. $H_0: \mu < \$9.74$ $H_a: \mu \ge \$9.74$ ?. $H_0: \mu = \$9.74$ $H_a: \mu \neq \$9.74$ ? ?. $H_0: \mu = \$9.74$ $H_a: \mu < \$9.74$ Determine whether all of the conditions have been met for this hypothesis test. Select all that apply. A. Yes, all of the conditions have been met. B. No, because the random sample and independence condition has not been met. C. No, because the big population condition has not been met. D. No, because the large sample condition has not been met. The test statistic is (Round to two decimal places as needed.) ? C. $H_0: \mu > \$9.74$ $H_a: \mu \le \$9.74$ ? ?. $H_0: \mu = \$9.74$ $H_a: \mu > \$9.74$

          The average price for a movie ticket in a certain country in 2018 was $9.74. A random sample of 34 movie ticket prices in a major city in that country had a sample mean of $13.15 with a standard deviation of $3.09.
a. Do we have evidence that the price of a movie ticket in that city is different from the national average? Use a significance level of 0.05.
b. Construct a 95% confidence interval for the price of a movie ticket in that city. How does your confidence interval support your conclusion in part (a)?
a. Determine the null and alternative hypotheses. Choose the correct answer below.
? ?. $H_0: \mu \neq \$9.74$
$H_a: \mu = \$9.74$
? D. $H_0: \mu < \$9.74$
$H_a: \mu \ge \$9.74$
?. $H_0: \mu = \$9.74$
$H_a: \mu \neq \$9.74$
? ?. $H_0: \mu = \$9.74$
$H_a: \mu < \$9.74$
Determine whether all of the conditions have been met for this hypothesis test. Select all that apply.
A. Yes, all of the conditions have been met.
B. No, because the random sample and independence condition has not been met.
C. No, because the big population condition has not been met.
D. No, because the large sample condition has not been met.
The test statistic is 
(Round to two decimal places as needed.)
? C. $H_0: \mu > \$9.74$
$H_a: \mu \le \$9.74$
? ?. $H_0: \mu = \$9.74$
$H_a: \mu > \$9.74$

The average price for a movie ticket in a certain country in 2018 was 9.74. A random sample of 34 movie ticket prices in a major city in that country had a sample mean of13.15 with a standard deviation of 3.09.
a. Do we have evidence that the price of a movie ticket in that city is different from the national average? Use a significance level of 0.05.
b. Construct a 95% confidence interval for the price of a movie ticket in that city. How does your confidence interval support your conclusion in part (a)?
a. Determine the null and alternative hypotheses. Choose the correct answer below.
? ?.H0: μ≠$9.74Ha: μ= $9.74? D.H0: μ< $9.74Ha: μ≥$9.74?.H0: μ= $9.74Ha: μ≠$9.74? ?.H0: μ= $9.74Ha: μ< $9.74Determine whether all of the conditions have been met for this hypothesis test. Select all that apply.
A. Yes, all of the conditions have been met.
B. No, because the random sample and independence condition has not been met.
C. No, because the big population condition has not been met.
D. No, because the large sample condition has not been met.
The test statistic is
(Round to two decimal places as needed.)
? C.H0: μ> $9.74Ha: μ≤$9.74? ?.H0: μ= $9.74Ha: μ> $9.74

Added by Jeremiah C.

Question

Please give Ace some feedback