Question

Consider the system shown in the figure (a), design a lead compensator $G_c(s)$, as shown in figure (b) so that the dominant closed-loop poles have the damping ratio $\zeta = 0.5$ and the undamped natural frequency $\omega_n = 3$ rad/s.

          Consider the system shown in the figure (a), design a lead compensator $G_c(s)$, as shown in figure (b) so that the dominant closed-loop poles have the damping ratio $\zeta = 0.5$ and the undamped natural frequency $\omega_n = 3$ rad/s.
        
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Consider the system shown in the figure (a), design a lead compensator Gc(s), as shown in figure (b) so that the dominant closed-loop poles have the damping ratio ζ = 0.5 and the undamped natural frequency = 3 rad/s.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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I need help with this as soon as possible, please. Solving it on a piece of paper would be great. Thanks in advance! Consider the system shown in figure (a) and design a lead compensator Gc(s) as shown in figure (b) so that the dominant closed-loop poles have a damping ratio (ζ) of 0.5 and an undamped natural frequency (ωn) of 3 rad/s. R(s) 10s(s + 1) C(s) R(s) 10s(s + 1) C(s) G(s) G(s) (a) (b)
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Transcript

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00:01 To solve this question for calculating zeros we will be using this equation s plus 4 is equals to 0 and s will come as minus 4.
00:10 4 poles, 4 poles, a square plus 3s plus 9 is equals to 0 and hence here on solving this quadratic equation we will get two values of s.
00:23 It will be s is equals to minus 3 plus minus root 27 divided by 3 and here another thing here will be minus 3 divided by 2 plus minus 3 divided by 2 root 3j.
00:41 So for this pole, pole zero diagram will be like this.
00:52 We will make cartesian coordinate here like this and here 0 minus 1 minus sorry this will be positive 1 positive 2 plus 3 and between plus 3 divided by 2 root 2.
01:23 So and here it will be minus 1 minus 1 .5 and here it will be minus 2 and minus 3.
01:35 So in the cartesian coordinate this point will be somewhere over here and here we will mark this as minus 1 .5 comma 1 .5 root 3 and here in the third quadrant we will have plus 2 minus of 3 divided by 2 root 3 and here this will be the point minus 1 .5 comma minus 1 .5 root 3...
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