6. Determine the slope of this line segment. [3 marks...

6. Determine the slope of this line segment. [3 marks App] 7. Graph the following lines on a grid. a) x = 3 [1 mark K&U] b) y = -2 [1 mark K&U] c) y = 4x – 3 [2 marks K&U] d) y = -?x + 6 [2 marks K&U] e) 2x – 7y = 14 [3 marks K&U] 8. Determine the x and y-intercepts for each of the following and use them to graph each line. a) 2x + 5y – 20 = 0 [4 marks App] b) 3x – 4y + 12 = 0 [4 marks App]

Transcript

00:01 So for number six, we are given a graph and we want to determine the slope of the line.

00:07 You can see that there's a point at 1 -2 and another marked point at 7 -6.

00:28 So right about up here.

00:33 Let me just move that.

00:35 So there's no mistaking.

00:36 This is 1 -2 and 7 -6.

00:40 So to find slope, i'm going to find the change in the ys.

00:44 So 6 minus 2 over the change in the x's.

00:48 That is going to give me 4 over 6.

00:51 I'm going to reduce that.

00:53 My slope is 2 thirds.

00:56 Let's do some quick graphing for 7a.

01:00 We want to graph x equals 3.

01:03 So that is a vertical line through positive 3 on the x -axis.

01:10 Y equals negative 2.

01:13 That is a horizontal line through negative 2 on the y axis.

01:22 Y equals 4x minus 3.

01:26 I'm going to go to negative 3, put a point, that's my y intercept, and then my slope is 4 over 1.

01:33 So i'm going to go up 4 and over 1 and put a second point and connect them with a line.

01:43 Negative 2 thirds x plus 6 i'm going to go to positive 6 put a point that's my y intercept now i'm going to go down to and to the right 3 and put a second point because my slope is a negative 2 thirds and now the last one in that section is 2x minus 7y is 14 so i'm going to use intercepts to graph this one.

02:19 I'm going to let x be zero.

02:23 So i have negative 7y equals 14...

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