Question

I Raindrops acquire an electric charge as they fall. Suppose a 2.0-mm-diameter drop has a charge of $+12 \mathrm{pC} ;$ these are both very common values. In a thunderstorm, the electric field under a cloud can reach $15,000 \mathrm{N} / \mathrm{C},$ directed upward. For a droplet exposed to this field, how do the magnitude and direction of the electric force compare to those of the weight force?

Name: I Raindrops acquire an electric charge as they fall. Suppose a 2.0-mm-diameter drop has a charge of +12 pC ; these are both very common values. In a thunderstorm, the electric field under a cloud can reach 15,000 N / C, directed upward. For a droplet exposed to this field, how do the magnitude and direction of the electric force compare to those of the weight force?
Uploaded: 2022-01-26T14:51:03-08:00
Duration: 3 min 53 s
Channel: Vishal Gupta
Description: I Raindrops acquire an electric charge as they fall. Suppose a 2.0-mm-diameter drop has a charge of +12 pC ; these are both very common values. In a thunderstorm, the electric field under a cloud can reach 15,000 N / C, directed upward. For a droplet exposed to this field, how do the magnitude and direction of the electric force compare to those of the weight force?

          I Raindrops acquire an electric charge as they fall. Suppose a 2.0-mm-diameter drop has a charge of $+12 \mathrm{pC} ;$ these are both very common values. In a thunderstorm, the electric field under a cloud can reach $15,000 \mathrm{N} / \mathrm{C},$ directed upward. For a droplet exposed to this field, how do the magnitude and direction of the electric force compare to those of the weight force?

Added by Mary W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Vishal Gupta

01/26/2022

Step 1

Given: Charge, q = $+12 \mathrm{pC} = 12 \times 10^{-12} \mathrm{C}$ Electric field, E = $15,000 \mathrm{N/C} = 15,000 \mathrm{V/m}$ The formula for electric force is: \[ F_E = q \times E \] Substitute the values: \[ F_E = 12 \times 10^{-12} \times 15,000 \] \[ Show more…

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I Raindrops acquire an electric charge as they fall. Suppose a 2.0-mm-diameter drop has a charge of $+12 \mathrm{pC} ;$ these are both very common values. In a thunderstorm, the electric field under a cloud can reach $15,000 \mathrm{N} / \mathrm{C},$ directed upward. For a droplet exposed to this field, how do the magnitude and direction of the electric force compare to those of the weight force?