I see restriction of range here a yes b no neo ezscore 300 s...

I see restriction of range here. A. yes B. no NEO Ezscore 300 S. Oishi et al./Journal of Research in Personality 58 (2015) 55-68 20000 25000 Elevation Difference r=-.40, p<.01 Fig. 1. The inversion between elevation difference (Highest Point Lowest Point) and extraversion in Study 3. Chapter 8 Review I see a curvilinear relationship here. A. yes B. no S. Oishi et al./Journal of Research in Personality 58 (2015) 55-68 NEO E zscore 3.00- 200 10000 15000 20000 25000 Elevation Difference r=-.40, p<.01 Fig. 1. The inverse correlation between elevation difference (Highest Point-Lowest Point) and extraversion in Study 3.

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00:01 I have students in this question first we need to check if there is a relationship between v and s and between v and e so we can do this by checking if the correlation coefficient are significantly different from 0 so we can use a t -test for this we can use a t -test for this so the null hypothesis is that the correlation coefficient is 0 null hypothesis is that the correlation coefficient r is equal to 0 and alternative hypothesis is that the alternative hypothesis is that it is different from 0 r is different from 0 different from 0 so we can use a two -tailed test because we don't know the direction of the relationship so here the critical value for a two -tailed test it is a two -tailed test with four degrees of freedom four degrees of freedom and n -2 so and after that and alpha equal to here alpha is equal to 0 .05 so here the critical value the critical value is equal to 2 .776 so we can use the formula that is t is equal to t equal to r into square root of n minus 2 divided by divided by divided by square root of 1 minus r square so to calculate the t value we can also use the p value to check if it is less than alpha so here are the calculations for v and s's so for v and s's are equal to 0 .43 and equal to 6 t equal to 0 .43 into square root of 6 minus 2 divided by square root of 1 minus 0 .43 square so after calculating this we get the value is equal to 1 .56 and p equal to 0 .175 using a two -tailed test and for v and e, r value is equal to 0 .14 and equal to 6 and t equal to 0 .14 into square root of 6 minus 2 divided by square root of 1 minus 0 .14 square so the value t value is equal to t value equal to 0 .51 and here p value is equal to here p value is equal to 0 .631 using a two -tailed test.

03:47 The t value for v and s's is less than the critical value critical value but the p value is greater than alpha greater than alpha so therefore we fail to reject null hypothesis and conclude that there is not a significant relationship between there is not a significant relationship between relationship between v and s's v and s's...

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