(i) Why can’t we compute the Taylor polynomial of ln(x) about a = 0? (ii) Write out the Taylor polynomial at x, about a = 0, of degree 5 for f (x) = ln(1 + x), along with the corresponding remainder. (iii) Give an upper bound for this remainder when x = 0, x = 0.01 and x = 0.1. (iv) How does the derivative of the Taylor polynomial found in part (ii) compare to the fourth-order Taylor polynomial about a = 0 for f (x) = 1/(1 + x)?