Question

I=868\times 10^(-9)m^(4), Centroid of the cross-section from bottom ()/(bar) (y)=38mm 5-kNI=3.04\times 10^(-6)m^(4)

Name: i868times 10 9m4 centroid of the cross section from bottom bar y38mm 5 kni304times 10 6m4 31625
Uploaded: 2023-09-24T13:34:49-08:00
Duration: 3 min 23 s
Channel: Sri K
Description: i868times 10 9m4 centroid of the cross section from bottom bar y38mm 5 kni304times 10 6m4 31625

          I=868\times 10^(-9)m^(4), Centroid of the cross-section from bottom ()/(bar) (y)=38mm 5-kNI=3.04\times 10^(-6)m^(4)

Added by Aitor M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

09/24/2023

Step 1

A cast-iron machine part is acted upon by the 3 kN.m couple shown. Neglecting the effect of fillets, determine the maximum tensile and compressive stresses in the casting. (I = 868x10⁻⁹ m⁴, Centroid of the cross-section from bottom $\bar{y}$ = 38 mm ) M = 3 kN Show more…

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