Question

2. A) For the circuit biased as shown below, given that ? = 120, calculate: i) Ic ii) VCE iii) Ib iv) VE v) Va 2 B) For the BJT differential amplifier shown below, Vcc = 10V, VEE = -10V, Vi = 1 mA, R1 = 12kohm, RE = 10 kohm, ? = 100, VA = ?, r = 25 kohm and Ra = 0. For one sided output at Vcr, calculate the voltage gain Av, the common mode gain Ac and the CMRR. $I_c = \frac{26 mV}{R_E}$ $A_v = \frac{\frac{\beta R_C}{r_e}}{1 + \frac{\beta R_C}{r_e}}$ $A_c = \frac{1}{2(\beta + 1)R_E}$ CMRR (log) = 20 log$_{10} \frac{A_v}{A_c}$ (dB)

          2. A) For the circuit biased as shown below, given that ? = 120, calculate:
i) Ic
ii) VCE
iii) Ib
iv) VE
v) Va
2 B) For the BJT differential amplifier shown below, Vcc = 10V, VEE = -10V,
Vi = 1 mA, R1 = 12kohm, RE = 10 kohm, ? = 100, VA = ?, r = 25 kohm and Ra = 0.
For one sided output at Vcr, calculate the voltage gain Av, the common mode gain Ac and the
CMRR.
$I_c = \frac{26 mV}{R_E}$
$A_v = \frac{\frac{\beta R_C}{r_e}}{1 + \frac{\beta R_C}{r_e}}$
$A_c = \frac{1}{2(\beta + 1)R_E}$
CMRR (log) = 20 log$_{10} \frac{A_v}{A_c}$ (dB)

2. A) For the circuit biased as shown below, given that ? = 120, calculate:
i) Ic
ii) VCE
iii) Ib
iv) VE
v) Va
2 B) For the BJT differential amplifier shown below, Vcc = 10V, VEE = -10V,
Vi = 1 mA, R1 = 12kohm, RE = 10 kohm, ? = 100, VA = ?, r = 25 kohm and Ra = 0.
For one sided output at Vcr, calculate the voltage gain Av, the common mode gain Ac and the
CMRR.
Ic = (26 mV)/(RE)
Av = ((β RC)/(re))/(1 + (β RC)/(re))
Ac = (1)/(2(β + 1)RE)
CMRR (log) = 20 log10(Av)/(Ac) (dB)

Added by Ivan C.

Question

Please give Ace some feedback