Question

iClicker 13.1 Let \( X \) be a random variable with \( P(X=1)=0.2, P(X=2)=0.3 \) and \( P(X=3)=0.5 \). What is the variance of \( X \) ? (c) 0.1892 \[ \operatorname{Var}(x)=E[(x . \] (C) 0.4675 (c) 0.5219 (1.) 0.6784 (c) 0.7810

          iClicker 13.1

Let \( X \) be a random variable with \( P(X=1)=0.2, P(X=2)=0.3 \) and \( P(X=3)=0.5 \). What is the variance of \( X \) ?
(c) 0.1892
\[
\operatorname{Var}(x)=E[(x .
\]
(C) 0.4675
(c) 0.5219
(1.) 0.6784
(c) 0.7810

iClicker 13.1

Let X be a random variable with P(X=1)=0.2, P(X=2)=0.3 and P(X=3)=0.5. What is the variance of X ?
(c) 0.1892

Var(x)=E[(x .

(C) 0.4675
(c) 0.5219
(1.) 0.6784
(c) 0.7810

Added by Amy C.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Hoan Nguyen

Step 1

\[ E(X) = \sum x_i \cdot P(X = x_i) = 1 \cdot 0.2 + 2 \cdot 0.3 + 3 \cdot 0.5 \] Show more…

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iClicker 13.1 Let \( X \) be a random variable with \( P(X=1)=0.2, P(X=2)=0.3 \) and \( P(X=3)=0.5 \). What is the variance of \( X \) ? (c) 0.1892 \[ \operatorname{Var}(x)=E[(x . \] (C) 0.4675 (c) 0.5219 (1.) 0.6784 (c) 0.7810