00:01
Here gamma for oxygen equals to 7 by 5 which is 1 .4.
00:09
Now we know that pv to the power gamma equals to constant for adiabatic process.
00:16
So p1 v1 to the power gamma equals to p2 v2 to the power gamma or we can write p2 equals to p1 v1 by v2 to the power gamma.
00:31
Now here p1 is 2 atmospheric pressure v1 by v2 is 3.
00:37
So 3 to the power 1 .4.
00:40
So p2 with this we have p2 equals to final pressure is 9 .31 atmospheric pressure.
00:55
This is for part 1.
00:58
Now for part 2, in part 2 we have to calculate the work done.
01:03
So work done pdv equals to nr dt.
01:12
Dt is the temperature change, n is the number of mole and r is universal gas constant.
01:18
So here n is 3 mole.
01:20
So n is 3 into 8 .31.
01:24
Dt change in temperature is 25 degree centigrade.
01:27
So this is equals to the work done equals to 623 .25 joule...