Question

Identify the conic for each equation below: 1. $5x^2 + 5y^2 + 10x + 5y - \frac{1}{2} = 0$ 2. $x^2 + y^2 - 2x - 4y - 4 = 0$ 3. $2x^2 - 2y^2 - 12x + 8y - 24 = 0$ 4. $y^2 + 4x - 4y + 4 = 0$ 5. $x^2 - 4x = 2y$ 6. $x^2 + 2y^2 = 9$ 7. $4x^2 - 3y^2 + 8x - 6y = 5$ 8. $y^2 - 4x^2 - 16x - 2y - 19 = 0$ Explain how you can identify the type of conic from the general equation without completing the square.

          Identify the conic for each equation below:
1. $5x^2 + 5y^2 + 10x + 5y - \frac{1}{2} = 0$
2. $x^2 + y^2 - 2x - 4y - 4 = 0$
3. $2x^2 - 2y^2 - 12x + 8y - 24 = 0$
4. $y^2 + 4x - 4y + 4 = 0$
5. $x^2 - 4x = 2y$
6. $x^2 + 2y^2 = 9$
7. $4x^2 - 3y^2 + 8x - 6y = 5$
8. $y^2 - 4x^2 - 16x - 2y - 19 = 0$
Explain how you can identify the type of conic from the general equation without completing the
square.

Identify the conic for each equation below:
1. 5x^2 + 5y^2 + 10x + 5y - (1)/(2) = 0
2. x^2 + y^2 - 2x - 4y - 4 = 0
3. 2x^2 - 2y^2 - 12x + 8y - 24 = 0
4. y^2 + 4x - 4y + 4 = 0
5. x^2 - 4x = 2y
6. x^2 + 2y^2 = 9
7. 4x^2 - 3y^2 + 8x - 6y = 5
8. y^2 - 4x^2 - 16x - 2y - 19 = 0
Explain how you can identify the type of conic from the general equation without completing the
square.

Added by James W.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Nick Johnson

Step 1

First, we need to rewrite the given equation in a more readable format: $$Sx^2 + 6y^2 + 10x + 5y - 34 = 0$$ Show more…

Show all steps

Thanks for your feedback!

Initially, it is given that the equation is conic, with the following coefficients: Sx' 6y' IOx 5 3-4; Zy' . 12* + 8y-24 = 0 Iv +8-ty _5 16x " Zy . 19-q. The task is to identify the type of conic and solve the equation without completing the square.