Question

Identical rays of light enter three transparent blocks composed of different materials at the same angle as shown in the picture. Light slows down upon entering the blocks. From the description of refraction angles, which block has the highest refractive index? Block 1 Block 2 Block 3 $\theta_1 < \theta_2 < \theta_3$ 

          Identical rays of light enter three transparent blocks composed of different materials at the same angle as shown in the picture. Light slows down upon entering the blocks. From the description of refraction angles, which block has the highest refractive index?
Block 1
Block 2
Block 3
$\theta_1 < \theta_2 < \theta_3$
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Identical rays of light enter three transparent blocks composed of different materials at the same angle as shown in the picture. Light slows down upon entering the blocks. From the description of refraction angles, which block has the highest refractive index? Block 1 Block 2 Block 3 θ1 < θ2 < θ3

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Identical rays of light enter three transparent blocks composed of different materials at the same angle as shown in the picture. Light slows down upon entering the blocks. From the description of refraction angles, which block has the highest refractive index? Block 1 Block 2 0 ******************* 0₁ <0, <0₂ Block 3 0
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Transcript

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00:01 So in this question here we see that n b divided by n is equal to 1 .6.
00:12 Now we use snail's law.
00:16 So this will sine i divided by sign r is equal to refractive index of medium medium with respect to air with respect to air.
00:38 Now in figure we say angle bad is equal to theta a or alternate angle.
00:56 Alternate angle so using snell's law using snell's law sin theta a divided by sine theta a, sine theta not divided by sine theta is equal to n.
01:17 Or, sine 60 degree divided by sine 20 degree is equal to n.
01:28 Now, sine theta a divided by sine theta b is equal to n b divided by n b.
01:38 So, sine theta a divided by sine 20 degree is equal to 1 .6.
01:50 So now, sine theta a is equal to 1 .6 multiplied by sine 20 degree, which comes 1 .6 multiplied by 0 .342.
02:06 So this comes 0 .547 or 0 .547 or theta is equal to 33 .16 degree.
02:28 So here we find out the thetae.
02:31 Now using theta a equation 1, we write sine 60 degree divided by sine 33 .16 is equal to so this one 0 .866 divided by 0 .547.
02:55 547 is equal to 1 .58 or n .a is equal to 1 .58.
03:06 So here we see that n b divided by n is equal to 1 .6.
03:14 So n b is equal to 1 .6...
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