00:03
Hi there.
00:04
In this question, we are trying to identify the bronstead -lowry bases in this chemical reaction.
00:10
So it's an equilibrium equation, so there should be one acid and one base on each side of the equation.
00:17
So let's start out with how we identify these.
00:19
A bronstead -lowry acid is defined as a proton donor, and a proton is an h -plus ion.
00:30
So it donates a proton.
00:35
Whereas a bronsted -lowry base is a proton.
00:39
Proton acceptor.
00:46
So in our equation, we need to look at where the transfer of a proton is occurring on each side of the equation.
00:56
So let's start with the first side.
00:57
And i wrote water as hoh, because that way it's easier to see the transfer of a proton.
01:05
Okay, so looking at the left side of the equation and the right side, the right side, we see that water, hoh, has become just ohh on the product side.
01:15
And our c5h5n has an extra hydrogen on the product side...