00:01
We have given a reaction where this is the reactant which is 1, 2, this is 1, 2 dimethylbenzene, dimethylbenzene.
00:17
What will be the product formation in presence of the reagents na, ch3oh and nh3? so, let us see the mechanism to find out the final product.
00:32
So, the mechanism will start from the reactant, we are taking 1, 2 dimethylbenzene here as the methyl group.
00:43
We are giving the sodium ion na.
00:47
What will happen? this bond will shift to this bond and the bond will go to this carbon atom that is why any positive will attack this carbon having negative charge.
00:59
That is why what will happen? there is the formation of negative charge and bond is shifted to this and here 2 methyl groups are present.
01:11
Now, to this we are giving ch3oh, we are writing the ch3oh in expanded form.
01:20
Oxygen is having lone pair of electrons.
01:23
So, what will happen? the bond will go to this.
01:25
That is why the negative charge will attract this hydrogen in presence of ammonia.
01:32
So, we will get the product...