00:01
Hello students in the question, we are given various scenarios for stretched string.
00:05
We have frequency of stretched ring.
00:20
It can be given by formula f.
00:24
It is equal to p divided by 2l under root p divided by m here.
00:33
We have f denotes frequency of string p.
00:47
It is number of harmonic p.
00:59
It is tension in string m.
01:12
It is linear mass density of string in l denotes length of string with a very first part that is tightening of string tightening of string results in increase in tension in the string and we know from this relation that frequency it is directly proportional to under root of tension.
02:17
So with increase in tension frequency also increases.
02:22
So in this case, we have increase in frequency of the string.
02:39
Next part we are replacing thin string with a thick string...