00:01
Before we find everything, we want to put it into general form.
00:03
So what i'm going to do is divide everything through by 1 ,024 and simplify it down to get the proper equation.
00:10
So this becomes x squared over 16, then minus y squared over, and that would become 64 is equal to 1.
00:18
So i know that this is going to be a squared, and i know this is going to be b squared, and then since x squared is written first, it's horizontal.
00:25
So the center is going to be found at 0 .0.
00:29
That's their 0 point.
00:30
Then from there we're going to go out the distance of a to get to the vertices.
00:34
So this is a distance at a.
00:35
There's your vertex.
00:36
And this will be the distance of a and there's your other vertex.
00:39
So because a in here is going to be four, because a squared is 16, this will be the point 4 comma 0 and then negative 4 comma 0.
00:50
So to find our focal points, what we need to do is find c.
00:54
So in a hyperbola, it's a squared plus b squared equals c squared.
00:58
So c squared is equal to 16 plus 64...