Question

If 0.150 moles of sodium nitrite were added to 2.00 L of a 0.0950 M solution of hydrochloric acid, wtwould the pH and the nitrite concentration of the solution be? (Ka = 4.5 X 104) Assume adding sodiumnitrite does not change the volume of the solution.

Name: if 0150 moles of sodium nitrite were added to 200 l of a 00950 m solution of hydrochloric acid wtwould the ph and the nitrite concentration of the solution be ka 45 x 104 assume adding sodiu 52605
Uploaded: 2022-08-20T06:55:01-08:00
Duration: 3 min 43 s
Channel: Adi S
Description: if 0150 moles of sodium nitrite were added to 200 l of a 00950 m solution of hydrochloric acid wtwould the ph and the nitrite concentration of the solution be ka 45 x 104 assume adding sodiu 52605

          If 0.150 moles of sodium nitrite were added to 2.00 L of a 0.0950 M solution of hydrochloric acid, wtwould the pH and the nitrite concentration of the solution be? (Ka = 4.5 X 104) Assume adding sodiumnitrite does not change the volume of the solution.

Added by Steven A.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

08/20/2022

Step 1

- The concentration of HCl is 0.0950 M and the volume is 2.00 L. - Moles of HCl = concentration × volume = 0.0950 mol/L × 2.00 L = 0.190 moles. Show more…

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If 0.150 moles of sodium nitrite were added to 2.00 L of a 0.0950 M solution of hydrochloric acid, wtwould the pH and the nitrite concentration of the solution be? (Ka = 4.5 X 104) Assume adding sodiumnitrite does not change the volume of the solution.