Question

If 1 L of 0.15 M of NaOH is unprotected from the air under standardization and absorbs 1.2 mmol of carbon dioxide, what will be the new molarity when it is standardized against standard solution of HCl using phenolphthalein? A. 0.13 M B. 0.15 M C. 0.1388 M D. 0.14 M

Name: if 1 lbog 015 m of naoh is unprotected from thw air under standardization and absorbs 12 mmol of carbon dioxide what will be the new molarity when it is standardized against standard solution of hcl u
Uploaded: 2023-11-30T11:36:36-08:00
Duration: 2 min 38 s
Channel: Anand Jangid
Description: if 1 lbog 015 m of naoh is unprotected from thw air under standardization and absorbs 12 mmol of carbon dioxide what will be the new molarity when it is standardized against standard solution of hcl u

          If 1 L of 0.15 M of NaOH is unprotected from the air under standardization and absorbs 1.2 mmol of carbon dioxide, what will be the new molarity when it is standardized against standard solution of HCl using phenolphthalein?

A. 0.13 M
B. 0.15 M
C. 0.1388 M
D. 0.14 M

Added by Nikka Feb A.

Chemistry

Raymond Chang 10th Edition

Chapter 16

Instant Answer

Solved by Expert Anand Jangid

11/30/2023

Step 1

15 M NaOH. Moles = Molarity x Volume Moles = 0.15 M x 1 Lbog = 0.15 mol Show more…

Show all steps

Thanks for your feedback!

If 1 L of 0.15 M of NaOH is unprotected from the air under standardization and absorbs 1.2 mmol of carbon dioxide, what will be the new molarity when it is standardized against standard solution of HCl using phenolphthalein? A. 0.13 M B. 0.15 M C. 0.1388 M D. 0.14 M