00:01
Hi, in this question we are asked to calculate final temperature when hot water and cold water are mixed with each other.
00:11
We are having mass of hot water, the temperature of hot water, mass of cold water and temperature of cold water.
00:20
We know that heat, there is q, is equal to mc delta t, where m is the mass, c is the specific heat of support.
00:30
And delta t is change in temperature.
00:33
In case of mixing we can say that heat is lost by hot water and that lost heat is gained by cold water.
00:57
Therefore we can write minus heat lost lost is equal to heat gain.
01:06
Here we can write mass of hot water specific heat of substance into delta t it is equal to mass of cold water specific heat of substance to delta t we can write here as mass of hot water into t final minus t hot water is equal to mass of cold water into t final minus t of cold water.
01:44
We can eliminate the specific heat of substance since it is common in both...