If (-1,3) is a point on the circle with center at the origin, find the equation of the tangent line to the circle at that point. y =
Added by Sonia M.
Step 1
Given that the center of the circle is at the origin (0,0) and the point (-1,3) lies on the circle, we can use the formula for the equation of a circle: (x - h)^2 + (y - k)^2 = r^2 Substitute the values of the point (-1,3) and the center (0,0) into the Show more…
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