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If 1.5 g of copper (II) nitrate is obtained from allowing 1.0 g of copper to react with an excess of nitric acid (according to your balanced equation of 4b), what is the percent yield of the reaction? 4b balanced equation: Cu(s) + 4 HNO3(aq) = Cu(NO3)2(aq) + 2 NO2(g) + 2 H2O(l)

Name: if 15 g of copper ii nitrate are obtained from allowing 10 g of copper to react with an excess of nitric acid according to your balanced equation of 4b what is the percent yield of the react 75744
Uploaded: 2022-10-29T15:54:51-08:00
Duration: 2 min 44 s
Channel: David Collins
Description: if 15 g of copper ii nitrate are obtained from allowing 10 g of copper to react with an excess of nitric acid according to your balanced equation of 4b what is the percent yield of the react 75744

          If 1.5 g of copper (II) nitrate is obtained from allowing 1.0 g of copper to react with an excess of nitric acid (according to your balanced equation of 4b), what is the percent yield of the reaction?
4b balanced equation: Cu(s) + 4 HNO3(aq) = Cu(NO3)2(aq) + 2 NO2(g) + 2 H2O(l)

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Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert David Collins

10/29/2022

Step 1

Given: Mass of copper = 1.0 g Molar mass of copper = 63.546 g/mol Number of moles of copper = Mass / Molar mass Number of moles of copper = 1.0 g / 63.546 g/mol Number of moles of copper = 0.0157 mol Show more…

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If 1.5 g of copper (II) nitrate is obtained from allowing 1.0 g of copper to react with an excess of nitric acid (according to your balanced equation of 4b), what is the percent yield of the reaction? 4b balanced equation: Cu(s) + 4 HNO3(aq) = Cu(NO3)2(aq) + 2 NO2(g) + 2 H2O(l)