If 1.50 moles of nitrogen gas reacts with an excess of hydrogen gas to produce a certain amount of ammonia, according to the following reaction: N2 (g) + H2 (g) → NH3 (g), what amount of ammonia (in grams) would be produced?
Added by Timothy B.
Step 1
The balanced equation is: N2 (g) + 3H2 (g) → 2NH3 (g). This tells us that 1 mole of nitrogen gas reacts with 3 moles of hydrogen gas to produce 2 moles of ammonia. Since we have 1.50 moles of nitrogen gas, and the reaction produces 2 moles of ammonia for every Show more…
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