Question

If 16 g of AX2 is reacted with excess X2 to give 18 g of AX3, what is the percent yield of AX3? 2 AX2 (g) + X2 (g) → 2 AX3 (g) Note that the molar mass of AX2 is 64.07 g/mol Note that the molar mass of AX3 is 80.06 g/mol Note that AX2, X2, and AX3 are hypothetical compounds.

Name: if 16 g of ax2 is reacted with excess x2 to give 18 g of ax3 what is the percent yield of ax3 2 ax2 g x2 g 2 ax3 g note that the molar mass of ax2 is 6407 gmol note that the molar mass of ax 02677
Uploaded: 2020-11-28T05:45:29-08:00
Duration: 2 min 16 s
Channel: Zubair Abdulla
Description: if 16 g of ax2 is reacted with excess x2 to give 18 g of ax3 what is the percent yield of ax3 2 ax2 g x2 g 2 ax3 g note that the molar mass of ax2 is 6407 gmol note that the molar mass of ax 02677

          If 16 g of AX2 is reacted with excess X2 to give 18 g of AX3, what is the percent yield of AX3? 2 AX2 (g) + X2 (g) → 2 AX3 (g) Note that the molar mass of AX2 is 64.07 g/mol Note that the molar mass of AX3 is 80.06 g/mol Note that AX2, X2, and AX3 are hypothetical compounds.

Added by Jaime N.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Zubair Abdulla

11/28/2020

Step 1

To calculate the number of moles, we can use the formula: moles = mass / molar mass Given that the mass of AX2 is 16 g and the molar mass is 64.07 g/mol, we can calculate: moles of AX2 = 16 g / 64.07 g/mol = 0.25 mol Show more…

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If 16 g of AX2 is reacted with excess X2 to give 18 g of AX3, what is the percent yield of AX3? 2 AX2 (g) + X2 (g) → 2 AX3 (g) Note that the molar mass of AX2 is 64.07 g/mol Note that the molar mass of AX3 is 80.06 g/mol Note that AX2, X2, and AX3 are hypothetical compounds.