If 23.1 g of TNT is combusted in a 0.205 L container filled with O2 at a pressure of 3.12 bar and a temperature of 298 K, calculate the maximum mass of CO2 that could be produced.
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Trinitrotoluene (TNT, C7H5N3O6) undergoes complete combustion according to the following balanced chemical equation: C7H5N3O6(s) + 21/4O2(g) → 7CO2(g) + 3/2N2(g) + 5/2H2O(l) If 27.0 g of TNT is combusted in a 0.400 L container filled with O2 at a pressure of 6.92 bar and a temperature of 298 K, calculate the maximum mass of CO2 that could be produced. Express your answer to two significant figures.
Ma Ednelyn L.
Trinitrotoluene (TNT, C7H5N3O6) undergoes complete combustion according to the following balanced chemical equation: C7H5N3O6(s) + 21/4 O2(g) -> 7 CO2(g) + 3/2 N2(g) + 5/2 H2O(l) Part A If 26.1 g of TNT is combusted in a 0.450 L container filled with O2 at a pressure of 5.00 bar and a temperature of 298 K, calculate the maximum mass of CO2 that could be produced. Express your answer to two significant figures.
Oluwapelumi K.
The combustion of TNT (trinitrotoluene, MM=227.13) in oxygen is given by the following equation: C7H5N3O6 (s) + O2 (g) → N2 (g) + H2O (g) + CO2 (g) (not balanced). Calculate the total volume (in L) of gas (at 149.0 °C and 144.0 kPa) produced by the complete decomposition of 1.300 kg of trinitrotoluene. (Assume the reaction is carried out in excess O2).
Supreeta N.
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