If 25.0 mL of 0.0500M an acid is being titrated with strong base and the equivalence point is reached at 20.0 mL of base, what is the concentration of the base?
Added by Vanessa P.
Step 1
Given: Volume of acid = 25.0 mL = 0.025 L Concentration of acid = 0.0500 M Moles of acid = Volume x Concentration Moles of acid = 0.025 L x 0.0500 mol/L Moles of acid = 0.00125 mol Show more…
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