If 25.0 ml of 0.200 M benzoic acid, Ka = 6.50 x 10-5, is titrated with 0.250 M NaOH, what is the pH after 15.0 ml of base have been added
Added by Michelle A.
Step 1
Calculate the initial moles of benzoic acid (HA) and NaOH (OH-). moles of HA = volume x concentration = 25.0 mL x 0.200 M = 5.00 mmol moles of OH- = volume x concentration = 15.0 mL x 0.250 M = 3.75 mmol Show more…
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