If 30.15 mL of 0.0995 M NaOH is required to neutralize 0.279 g of an unknown acid, HA, what is the molar mass of the unknown acid?
Added by Jessica K.
Step 1
First, we need to find the moles of NaOH used in the reaction. We can do this by multiplying the volume (in liters) by the molarity: Moles of NaOH = (0.03015 L) × (0.0995 mol/L) = 0.002999925 mol Show more…
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