If 35.4 g of NO and 26.9 g of O₂ react together, how many grams of NO₂ can be formed via the reaction below? 2 NO (g) + O₂ (g) → 2 NO₂ (g)?
Added by Brandy D.
Step 1
First, we need to find the number of moles of each reactant. Number of moles = mass (g) / molar mass (g/mol) For NO: Molar mass of NO = 14.01 (N) + 16.00 (O) = 30.01 g/mol Number of moles of NO = 35.4 g / 30.01 g/mol = 1.1796 mol For O₂: Molar mass of O₂ = 2 * Show more…
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