If 4 of a company's 10 delivery trucks do not meet emission standards and 3 of them are chosen for inspection, what is the probability that exactly two of the trucks chosen will meet emission standards? Select one: None 30% ≈3.33% 50% ≈96.67%
Added by Michael H.
Step 1
This can be calculated using combinations: Total combinations = C(10,3) = $\frac{10!}{3!(10-3)!}$ = $\frac{10!}{3!7!}$ = 120 Now, we need to find the number of ways to choose exactly 2 trucks that meet emission standards and 1 truck that does not. There are 6 Show more…
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