If $4000 is invested at an interest rate of 9.25% per year; compounded continuously; find the value of the investment after the given number of years. (Round your answers to the nearest cent ) (a) 3 years (b) 6 years
Added by Larry C.
Step 1
0925 \times 3} \] \[ y = 4000 \times e^{0.2775} \] \[ y = 4000 \times 1.3197 \] \[ y = 5278.80 \] Show more…
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