If 42.7 mL of 0.216 M HCl solution is needed to neutralize a solution of Ca(OH)2, how many grams of Ca(OH)2 must be in the solution? Express the mass in grams to three significant digits.
Added by Susana K.
Step 1
Given: Volume of HCl solution (V) = 42.7 mL = 0.0427 L Molarity of HCl solution (M) = 0.216 M Moles of HCl = Molarity x Volume Moles of HCl = 0.216 mol/L x 0.0427 L Moles of HCl = 0.009232 mol Show more…
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