If 5.50 mol of calcium carbide (CaC) reacts with an excess of water, how many moles of acetylene(C2H2), a gas used in welding, will be produced? CaC2(s) +2H2O Ca(OH)2(aq) +C2H2(g)
Added by Willie B.
Step 1
The balanced equation is already given in the question: \[ \text{CaC}_2(s) + 2\text{H}_2\text{O}(l) \rightarrow \text{Ca(OH)}_2(aq) + \text{C}_2\text{H}_2(g) \] Show more…
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If 4.40 mol of calcium carbide (CaC2) reacts with an excess of water, how many moles of acetylene (C2H2), a gas used in welding, will be produced? CaC2(s) + 2 H2O(l) Ca(OH)2(aq) + C2H2(g)
Jennifer H.
Welding If 5.50 mol of calcium carbide $\left(\mathrm{CaC}_{2}\right)$ reacts with an excess of water, how many moles of acetylene $\left(\mathrm{C}_{2} \mathrm{H}_{2}\right),$ a gas used in welding, will be produced? \begin{equation} \mathrm{CaC}_{2}(\mathrm{s})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{aq})+\mathrm{C}_{2} \mathrm{H}_{2}(\mathrm{g}) \end{equation}
Calcium carbide reacts with water to produce acetylene and calcium hydroxide: $$ \mathrm{CaC}_{2}(\mathrm{s})+2 \mathrm{H}_{2} \mathrm{O}(\ell) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{2}(\mathrm{g})+\mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{s}) $$ Suppose you combine $13.0 \mathrm{g}$ of $\mathrm{CaC}_{2}$ with $4.65 \mathrm{g}$ of water and collect the acetylene in a $4.66-\mathrm{L}$. flask. What is the pressure of the acetylene at $23^{\circ} \mathrm{C} ?$
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